Metamath Proof Explorer
		
		
		
		Description:  The original expressions are also in the closure.  (Contributed by Mario
       Carneiro, 18-Jul-2016)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | mclsval.d | ⊢ 𝐷  =  ( mDV ‘ 𝑇 ) | 
					
						|  |  | mclsval.e | ⊢ 𝐸  =  ( mEx ‘ 𝑇 ) | 
					
						|  |  | mclsval.c | ⊢ 𝐶  =  ( mCls ‘ 𝑇 ) | 
					
						|  |  | mclsval.1 | ⊢ ( 𝜑  →  𝑇  ∈  mFS ) | 
					
						|  |  | mclsval.2 | ⊢ ( 𝜑  →  𝐾  ⊆  𝐷 ) | 
					
						|  |  | mclsval.3 | ⊢ ( 𝜑  →  𝐵  ⊆  𝐸 ) | 
				
					|  | Assertion | ssmcls | ⊢  ( 𝜑  →  𝐵  ⊆  ( 𝐾 𝐶 𝐵 ) ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | mclsval.d | ⊢ 𝐷  =  ( mDV ‘ 𝑇 ) | 
						
							| 2 |  | mclsval.e | ⊢ 𝐸  =  ( mEx ‘ 𝑇 ) | 
						
							| 3 |  | mclsval.c | ⊢ 𝐶  =  ( mCls ‘ 𝑇 ) | 
						
							| 4 |  | mclsval.1 | ⊢ ( 𝜑  →  𝑇  ∈  mFS ) | 
						
							| 5 |  | mclsval.2 | ⊢ ( 𝜑  →  𝐾  ⊆  𝐷 ) | 
						
							| 6 |  | mclsval.3 | ⊢ ( 𝜑  →  𝐵  ⊆  𝐸 ) | 
						
							| 7 |  | eqid | ⊢ ( mVH ‘ 𝑇 )  =  ( mVH ‘ 𝑇 ) | 
						
							| 8 | 1 2 3 4 5 6 7 | ssmclslem | ⊢ ( 𝜑  →  ( 𝐵  ∪  ran  ( mVH ‘ 𝑇 ) )  ⊆  ( 𝐾 𝐶 𝐵 ) ) | 
						
							| 9 | 8 | unssad | ⊢ ( 𝜑  →  𝐵  ⊆  ( 𝐾 𝐶 𝐵 ) ) |