Metamath Proof Explorer


Theorem subiwrd

Description: Lemma for sseqp1 . (Contributed by Thierry Arnoux, 25-Apr-2019)

Ref Expression
Hypotheses iwrdsplit.s ⊢ ( 𝜑 → 𝑆 ∈ V )
iwrdsplit.f ⊢ ( 𝜑 → 𝐹 : ℕ0 ⟶ 𝑆 )
iwrdsplit.n ⊢ ( 𝜑 → 𝑁 ∈ ℕ0 )
Assertion subiwrd ( 𝜑 → ( 𝐹 ↾ ( 0 ..^ 𝑁 ) ) ∈ Word 𝑆 )

Proof

Step Hyp Ref Expression
1 iwrdsplit.s ⊢ ( 𝜑 → 𝑆 ∈ V )
2 iwrdsplit.f ⊢ ( 𝜑 → 𝐹 : ℕ0 ⟶ 𝑆 )
3 iwrdsplit.n ⊢ ( 𝜑 → 𝑁 ∈ ℕ0 )
4 fzo0ssnn0 ⊢ ( 0 ..^ 𝑁 ) ⊆ ℕ0
5 fssres ⊢ ( ( 𝐹 : ℕ0 ⟶ 𝑆 ∧ ( 0 ..^ 𝑁 ) ⊆ ℕ0 ) → ( 𝐹 ↾ ( 0 ..^ 𝑁 ) ) : ( 0 ..^ 𝑁 ) ⟶ 𝑆 )
6 2 4 5 sylancl ⊢ ( 𝜑 → ( 𝐹 ↾ ( 0 ..^ 𝑁 ) ) : ( 0 ..^ 𝑁 ) ⟶ 𝑆 )
7 iswrdi ⊢ ( ( 𝐹 ↾ ( 0 ..^ 𝑁 ) ) : ( 0 ..^ 𝑁 ) ⟶ 𝑆 → ( 𝐹 ↾ ( 0 ..^ 𝑁 ) ) ∈ Word 𝑆 )
8 6 7 syl ⊢ ( 𝜑 → ( 𝐹 ↾ ( 0 ..^ 𝑁 ) ) ∈ Word 𝑆 )