Theorem suceqd

Description: Deduction associated with suceq . (Contributed by Rohan Ridenour, 8-Aug-2023)

	Ref	Expression
Hypothesis	suceqd.1	⊢ ( 𝜑 → 𝐴 = 𝐵 )
Assertion	suceqd	⊢ ( 𝜑 → suc 𝐴 = suc 𝐵 )

Proof

Step	Hyp	Ref	Expression
1		suceqd.1	⊢ ( 𝜑 → 𝐴 = 𝐵 )
2		suceq	⊢ ( 𝐴 = 𝐵 → suc 𝐴 = suc 𝐵 )
3	1 2	syl	⊢ ( 𝜑 → suc 𝐴 = suc 𝐵 )