Metamath Proof Explorer


Theorem suceqd

Description: Deduction associated with suceq . (Contributed by Rohan Ridenour, 8-Aug-2023)

Ref Expression
Hypothesis suceqd.1 φA=B
Assertion suceqd φsucA=sucB

Proof

Step Hyp Ref Expression
1 suceqd.1 φA=B
2 suceq A=BsucA=sucB
3 1 2 syl φsucA=sucB