Metamath Proof Explorer


Theorem suceqd

Description: Deduction associated with suceq . (Contributed by Rohan Ridenour, 8-Aug-2023)

Ref Expression
Hypothesis suceqd.1 φ A = B
Assertion suceqd φ suc A = suc B

Proof

Step Hyp Ref Expression
1 suceqd.1 φ A = B
2 1 sneqd φ A = B
3 1 2 uneq12d φ A A = B B
4 df-suc suc A = A A
5 df-suc suc B = B B
6 3 4 5 3eqtr4g φ suc A = suc B