Metamath Proof Explorer


Theorem tglinesseq

Description: If a line is a subset of another line, they are equal. (Contributed by Thierry Arnoux, 17-Jun-2026)

Ref Expression
Hypotheses tglinesseq.l 𝐿 = ( LineG ‘ 𝐺 )
tglinesseq.g ( 𝜑𝐺 ∈ TarskiG )
tglinesseq.a ( 𝜑𝐴 ∈ ran 𝐿 )
tglinesseq.b ( 𝜑𝐵 ∈ ran 𝐿 )
tglinesseq.1 ( 𝜑𝐴𝐵 )
Assertion tglinesseq ( 𝜑𝐴 = 𝐵 )

Proof

Step Hyp Ref Expression
1 tglinesseq.l 𝐿 = ( LineG ‘ 𝐺 )
2 tglinesseq.g ( 𝜑𝐺 ∈ TarskiG )
3 tglinesseq.a ( 𝜑𝐴 ∈ ran 𝐿 )
4 tglinesseq.b ( 𝜑𝐵 ∈ ran 𝐿 )
5 tglinesseq.1 ( 𝜑𝐴𝐵 )
6 simplr ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝐴 = ( 𝑥 𝐿 𝑦 ) )
7 eqid ( Base ‘ 𝐺 ) = ( Base ‘ 𝐺 )
8 eqid ( Itv ‘ 𝐺 ) = ( Itv ‘ 𝐺 )
9 2 ad4antr ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝐺 ∈ TarskiG )
10 simp-4r ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝑥 ∈ ( Base ‘ 𝐺 ) )
11 simpllr ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝑦 ∈ ( Base ‘ 𝐺 ) )
12 simpr ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝑥𝑦 )
13 4 ad4antr ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝐵 ∈ ran 𝐿 )
14 5 ad4antr ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝐴𝐵 )
15 7 8 1 9 10 11 12 tglinerflx1 ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝑥 ∈ ( 𝑥 𝐿 𝑦 ) )
16 15 6 eleqtrrd ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝑥𝐴 )
17 14 16 sseldd ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝑥𝐵 )
18 7 8 1 9 10 11 12 tglinerflx2 ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝑦 ∈ ( 𝑥 𝐿 𝑦 ) )
19 18 6 eleqtrrd ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝑦𝐴 )
20 14 19 sseldd ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝑦𝐵 )
21 7 8 1 9 10 11 12 12 13 17 20 tglinethru ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝐵 = ( 𝑥 𝐿 𝑦 ) )
22 6 21 eqtr4d ( ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝐴 = ( 𝑥 𝐿 𝑦 ) ) ∧ 𝑥𝑦 ) → 𝐴 = 𝐵 )
23 22 anasss ( ( ( ( 𝜑𝑥 ∈ ( Base ‘ 𝐺 ) ) ∧ 𝑦 ∈ ( Base ‘ 𝐺 ) ) ∧ ( 𝐴 = ( 𝑥 𝐿 𝑦 ) ∧ 𝑥𝑦 ) ) → 𝐴 = 𝐵 )
24 7 8 1 2 3 tgisline ( 𝜑 → ∃ 𝑥 ∈ ( Base ‘ 𝐺 ) ∃ 𝑦 ∈ ( Base ‘ 𝐺 ) ( 𝐴 = ( 𝑥 𝐿 𝑦 ) ∧ 𝑥𝑦 ) )
25 23 24 r19.29vva ( 𝜑𝐴 = 𝐵 )