Metamath Proof Explorer


Theorem topfne

Description: Fineness for covers corresponds precisely with fineness for topologies. (Contributed by Jeff Hankins, 29-Sep-2009)

Ref Expression
Hypotheses topfne.1 ⊢ 𝑋 = ∪ 𝐽
topfne.2 ⊢ 𝑌 = ∪ 𝐾
Assertion topfne ( ( 𝐾 ∈ Top ∧ 𝑋 = 𝑌 ) → ( 𝐽 ⊆ 𝐾 ↔ 𝐽 Fne 𝐾 ) )

Proof

Step Hyp Ref Expression
1 topfne.1 ⊢ 𝑋 = ∪ 𝐽
2 topfne.2 ⊢ 𝑌 = ∪ 𝐾
3 tgtop ⊢ ( 𝐾 ∈ Top → ( topGen ‘ 𝐾 ) = 𝐾 )
4 3 sseq2d ⊢ ( 𝐾 ∈ Top → ( 𝐽 ⊆ ( topGen ‘ 𝐾 ) ↔ 𝐽 ⊆ 𝐾 ) )
5 4 bicomd ⊢ ( 𝐾 ∈ Top → ( 𝐽 ⊆ 𝐾 ↔ 𝐽 ⊆ ( topGen ‘ 𝐾 ) ) )
6 1 2 isfne4 ⊢ ( 𝐽 Fne 𝐾 ↔ ( 𝑋 = 𝑌 ∧ 𝐽 ⊆ ( topGen ‘ 𝐾 ) ) )
7 6 baibr ⊢ ( 𝑋 = 𝑌 → ( 𝐽 ⊆ ( topGen ‘ 𝐾 ) ↔ 𝐽 Fne 𝐾 ) )
8 5 7 sylan9bb ⊢ ( ( 𝐾 ∈ Top ∧ 𝑋 = 𝑌 ) → ( 𝐽 ⊆ 𝐾 ↔ 𝐽 Fne 𝐾 ) )