Metamath Proof Explorer


Theorem topfne

Description: Fineness for covers corresponds precisely with fineness for topologies. (Contributed by Jeff Hankins, 29-Sep-2009)

Ref Expression
Hypotheses topfne.1 ⊢ X = ⋃ J
topfne.2 ⊢ Y = ⋃ K
Assertion topfne ⊢ K ∈ Top ∧ X = Y → J ⊆ K ↔ J Fne K

Proof

Step Hyp Ref Expression
1 topfne.1 ⊢ X = ⋃ J
2 topfne.2 ⊢ Y = ⋃ K
3 tgtop ⊢ K ∈ Top → topGen ⁡ K = K
4 3 sseq2d ⊢ K ∈ Top → J ⊆ topGen ⁡ K ↔ J ⊆ K
5 4 bicomd ⊢ K ∈ Top → J ⊆ K ↔ J ⊆ topGen ⁡ K
6 1 2 isfne4 ⊢ J Fne K ↔ X = Y ∧ J ⊆ topGen ⁡ K
7 6 baibr ⊢ X = Y → J ⊆ topGen ⁡ K ↔ J Fne K
8 5 7 sylan9bb ⊢ K ∈ Top ∧ X = Y → J ⊆ K ↔ J Fne K