Metamath Proof Explorer


Theorem unhe1

Description: The union of two relations hereditary in a class is also hereditary in a class. (Contributed by RP, 28-Mar-2020)

Ref Expression
Assertion unhe1 ( ( 𝑅 hereditary 𝐴 ∧ 𝑆 hereditary 𝐴 ) → ( 𝑅 ∪ 𝑆 ) hereditary 𝐴 )

Proof

Step Hyp Ref Expression
1 df-he ⊢ ( 𝑅 hereditary 𝐴 ↔ ( 𝑅 “ 𝐴 ) ⊆ 𝐴 )
2 df-he ⊢ ( 𝑆 hereditary 𝐴 ↔ ( 𝑆 “ 𝐴 ) ⊆ 𝐴 )
3 imaundir ⊢ ( ( 𝑅 ∪ 𝑆 ) “ 𝐴 ) = ( ( 𝑅 “ 𝐴 ) ∪ ( 𝑆 “ 𝐴 ) )
4 unss ⊢ ( ( ( 𝑅 “ 𝐴 ) ⊆ 𝐴 ∧ ( 𝑆 “ 𝐴 ) ⊆ 𝐴 ) ↔ ( ( 𝑅 “ 𝐴 ) ∪ ( 𝑆 “ 𝐴 ) ) ⊆ 𝐴 )
5 4 biimpi ⊢ ( ( ( 𝑅 “ 𝐴 ) ⊆ 𝐴 ∧ ( 𝑆 “ 𝐴 ) ⊆ 𝐴 ) → ( ( 𝑅 “ 𝐴 ) ∪ ( 𝑆 “ 𝐴 ) ) ⊆ 𝐴 )
6 3 5 eqsstrid ⊢ ( ( ( 𝑅 “ 𝐴 ) ⊆ 𝐴 ∧ ( 𝑆 “ 𝐴 ) ⊆ 𝐴 ) → ( ( 𝑅 ∪ 𝑆 ) “ 𝐴 ) ⊆ 𝐴 )
7 1 2 6 syl2anb ⊢ ( ( 𝑅 hereditary 𝐴 ∧ 𝑆 hereditary 𝐴 ) → ( ( 𝑅 ∪ 𝑆 ) “ 𝐴 ) ⊆ 𝐴 )
8 df-he ⊢ ( ( 𝑅 ∪ 𝑆 ) hereditary 𝐴 ↔ ( ( 𝑅 ∪ 𝑆 ) “ 𝐴 ) ⊆ 𝐴 )
9 7 8 sylibr ⊢ ( ( 𝑅 hereditary 𝐴 ∧ 𝑆 hereditary 𝐴 ) → ( 𝑅 ∪ 𝑆 ) hereditary 𝐴 )