Metamath Proof Explorer


Theorem unitinvcl

Description: The inverse of a unit exists and is a unit. (Contributed by Mario Carneiro, 2-Dec-2014)

Ref Expression
Hypotheses unitinvcl.1 ⊢ 𝑈 = ( Unit ‘ 𝑅 )
unitinvcl.2 ⊢ 𝐼 = ( invr ‘ 𝑅 )
Assertion unitinvcl ( ( 𝑅 ∈ Ring ∧ 𝑋 ∈ 𝑈 ) → ( 𝐼 ‘ 𝑋 ) ∈ 𝑈 )

Proof

Step Hyp Ref Expression
1 unitinvcl.1 ⊢ 𝑈 = ( Unit ‘ 𝑅 )
2 unitinvcl.2 ⊢ 𝐼 = ( invr ‘ 𝑅 )
3 eqid ⊢ ( ( mulGrp ‘ 𝑅 ) ↾s 𝑈 ) = ( ( mulGrp ‘ 𝑅 ) ↾s 𝑈 )
4 1 3 unitgrp ⊢ ( 𝑅 ∈ Ring → ( ( mulGrp ‘ 𝑅 ) ↾s 𝑈 ) ∈ Grp )
5 1 3 unitgrpbas ⊢ 𝑈 = ( Base ‘ ( ( mulGrp ‘ 𝑅 ) ↾s 𝑈 ) )
6 1 3 2 invrfval ⊢ 𝐼 = ( invg ‘ ( ( mulGrp ‘ 𝑅 ) ↾s 𝑈 ) )
7 5 6 grpinvcl ⊢ ( ( ( ( mulGrp ‘ 𝑅 ) ↾s 𝑈 ) ∈ Grp ∧ 𝑋 ∈ 𝑈 ) → ( 𝐼 ‘ 𝑋 ) ∈ 𝑈 )
8 4 7 sylan ⊢ ( ( 𝑅 ∈ Ring ∧ 𝑋 ∈ 𝑈 ) → ( 𝐼 ‘ 𝑋 ) ∈ 𝑈 )