Metamath Proof Explorer


Theorem unon

Description: The class of all ordinal numbers is its own union. Exercise 11 of TakeutiZaring p. 40. (Contributed by NM, 12-Nov-2003)

Ref Expression
Assertion unon ∪ On = On

Proof

Step Hyp Ref Expression
1 eluni2 ⊢ ( 𝑥 ∈ ∪ On ↔ ∃ 𝑦 ∈ On 𝑥 ∈ 𝑦 )
2 onelon ⊢ ( ( 𝑦 ∈ On ∧ 𝑥 ∈ 𝑦 ) → 𝑥 ∈ On )
3 2 rexlimiva ⊢ ( ∃ 𝑦 ∈ On 𝑥 ∈ 𝑦 → 𝑥 ∈ On )
4 1 3 sylbi ⊢ ( 𝑥 ∈ ∪ On → 𝑥 ∈ On )
5 vex ⊢ 𝑥 ∈ V
6 5 sucid ⊢ 𝑥 ∈ suc 𝑥
7 onsuc ⊢ ( 𝑥 ∈ On → suc 𝑥 ∈ On )
8 elunii ⊢ ( ( 𝑥 ∈ suc 𝑥 ∧ suc 𝑥 ∈ On ) → 𝑥 ∈ ∪ On )
9 6 7 8 sylancr ⊢ ( 𝑥 ∈ On → 𝑥 ∈ ∪ On )
10 4 9 impbii ⊢ ( 𝑥 ∈ ∪ On ↔ 𝑥 ∈ On )
11 10 eqriv ⊢ ∪ On = On