Metamath Proof Explorer


Theorem xp0

Description: The Cartesian product with the empty set is empty. Part of Theorem 3.13(ii) of Monk1 p. 37. (Contributed by NM, 12-Apr-2004) Avoid axioms. (Revised by TM, 1-Feb-2026)

Ref Expression
Assertion xp0 ( 𝐴 × ∅ ) = ∅

Proof

Step Hyp Ref Expression
1 noel ⊢ ¬ 𝑦 ∈ ∅
2 simprr ⊢ ( ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ ∅ ) ) → 𝑦 ∈ ∅ )
3 1 2 mto ⊢ ¬ ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ ∅ ) )
4 3 nex ⊢ ¬ ∃ 𝑦 ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ ∅ ) )
5 4 nex ⊢ ¬ ∃ 𝑥 ∃ 𝑦 ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ ∅ ) )
6 elxpi ⊢ ( 𝑧 ∈ ( 𝐴 × ∅ ) → ∃ 𝑥 ∃ 𝑦 ( 𝑧 = ⟨ 𝑥 , 𝑦 ⟩ ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑦 ∈ ∅ ) ) )
7 5 6 mto ⊢ ¬ 𝑧 ∈ ( 𝐴 × ∅ )
8 7 nel0 ⊢ ( 𝐴 × ∅ ) = ∅