Metamath Proof Explorer


Theorem equsexv

Description: An equivalence related to implicit substitution. Version of equsex with a disjoint variable condition, which does not require ax-13 . See equsexvw for a version with two disjoint variable conditions requiring fewer axioms. See also the dual form equsalv . (Contributed by NM, 5-Aug-1993) (Revised by BJ, 31-May-2019)

Ref Expression
Hypotheses equsalv.nf
|- F/ x ps
equsalv.1
|- ( x = y -> ( ph <-> ps ) )
Assertion equsexv
|- ( E. x ( x = y /\ ph ) <-> ps )

Proof

Step Hyp Ref Expression
1 equsalv.nf
 |-  F/ x ps
2 equsalv.1
 |-  ( x = y -> ( ph <-> ps ) )
3 2 pm5.32i
 |-  ( ( x = y /\ ph ) <-> ( x = y /\ ps ) )
4 3 exbii
 |-  ( E. x ( x = y /\ ph ) <-> E. x ( x = y /\ ps ) )
5 ax6ev
 |-  E. x x = y
6 1 19.41
 |-  ( E. x ( x = y /\ ps ) <-> ( E. x x = y /\ ps ) )
7 5 6 mpbiran
 |-  ( E. x ( x = y /\ ps ) <-> ps )
8 4 7 bitri
 |-  ( E. x ( x = y /\ ph ) <-> ps )