Metamath Proof Explorer


Theorem equsexv

Description: An equivalence related to implicit substitution. Version of equsex with a disjoint variable condition, which does not require ax-13 . See equsexvw for a version with two disjoint variable conditions requiring fewer axioms. See also the dual form equsalv . (Contributed by NM, 5-Aug-1993) (Revised by BJ, 31-May-2019) Avoid ax-10 . (Revised by Gino Giotto, 18-Nov-2024)

Ref Expression
Hypotheses equsalv.nf 𝑥 𝜓
equsalv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
Assertion equsexv ( ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ 𝜓 )

Proof

Step Hyp Ref Expression
1 equsalv.nf 𝑥 𝜓
2 equsalv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
3 2 biimpa ( ( 𝑥 = 𝑦𝜑 ) → 𝜓 )
4 1 3 exlimi ( ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) → 𝜓 )
5 1 2 equsalv ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ 𝜓 )
6 equs4v ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
7 5 6 sylbir ( 𝜓 → ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
8 4 7 impbii ( ∃ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ 𝜓 )