Metamath Proof Explorer


Theorem goldratmolem4

Description: Lemma 4 for determining the value of golden ratio. (Contributed by Ender Ting, 24-Jul-2026)

Ref Expression
Hypothesis goldra.val
|- F = ( 2 x. ( cos ` ( _pi / 5 ) ) )
Assertion goldratmolem4
|- ( ( ( F ^ 2 ) - F ) - 1 ) = 0

Proof

Step Hyp Ref Expression
1 goldra.val
 |-  F = ( 2 x. ( cos ` ( _pi / 5 ) ) )
2 1 goldrarr
 |-  F e. RR
3 2re
 |-  2 e. RR
4 2 3 readdcli
 |-  ( F + 2 ) e. RR
5 1 goldrapos
 |-  0 < F
6 2pos
 |-  0 < 2
7 2 3 5 6 addgt0ii
 |-  0 < ( F + 2 )
8 4 7 gt0ne0ii
 |-  ( F + 2 ) =/= 0
9 8 neii
 |-  -. ( F + 2 ) = 0
10 2 recni
 |-  F e. CC
11 10 goldpolyfactor
 |-  ( ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) x. ( F + 2 ) ) = ( ( ( ( F ^ 5 ) - ( 5 x. ( F ^ 3 ) ) ) + ( 5 x. F ) ) + 2 )
12 1 goldratmolem3
 |-  ( ( ( ( F ^ 5 ) - ( 5 x. ( F ^ 3 ) ) ) + ( 5 x. F ) ) + 2 ) = 0
13 11 12 eqtri
 |-  ( ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) x. ( F + 2 ) ) = 0
14 10 sqcli
 |-  ( F ^ 2 ) e. CC
15 14 10 subcli
 |-  ( ( F ^ 2 ) - F ) e. CC
16 ax-1cn
 |-  1 e. CC
17 15 16 subcli
 |-  ( ( ( F ^ 2 ) - F ) - 1 ) e. CC
18 17 17 mulcli
 |-  ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) e. CC
19 2cn
 |-  2 e. CC
20 10 19 addcli
 |-  ( F + 2 ) e. CC
21 18 20 mul0ori
 |-  ( ( ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) x. ( F + 2 ) ) = 0 <-> ( ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) = 0 \/ ( F + 2 ) = 0 ) )
22 13 21 mpbi
 |-  ( ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) = 0 \/ ( F + 2 ) = 0 )
23 orcom
 |-  ( ( ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) = 0 \/ ( F + 2 ) = 0 ) <-> ( ( F + 2 ) = 0 \/ ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) = 0 ) )
24 22 23 mpbi
 |-  ( ( F + 2 ) = 0 \/ ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) = 0 )
25 9 24 mtpor
 |-  ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) = 0
26 17 msq0i
 |-  ( ( ( ( ( F ^ 2 ) - F ) - 1 ) x. ( ( ( F ^ 2 ) - F ) - 1 ) ) = 0 <-> ( ( ( F ^ 2 ) - F ) - 1 ) = 0 )
27 25 26 mpbi
 |-  ( ( ( F ^ 2 ) - F ) - 1 ) = 0