Metamath Proof Explorer


Theorem pw2divs0d

Description: Division into zero is zero for a power of two. (Contributed by Scott Fenton, 21-Feb-2026)

Ref Expression
Hypothesis pw2divs0d.1
|- ( ph -> N e. NN0_s )
Assertion pw2divs0d
|- ( ph -> ( 0s /su ( 2s ^su N ) ) = 0s )

Proof

Step Hyp Ref Expression
1 pw2divs0d.1
 |-  ( ph -> N e. NN0_s )
2 2sno
 |-  2s e. No
3 expscl
 |-  ( ( 2s e. No /\ N e. NN0_s ) -> ( 2s ^su N ) e. No )
4 2 1 3 sylancr
 |-  ( ph -> ( 2s ^su N ) e. No )
5 muls01
 |-  ( ( 2s ^su N ) e. No -> ( ( 2s ^su N ) x.s 0s ) = 0s )
6 4 5 syl
 |-  ( ph -> ( ( 2s ^su N ) x.s 0s ) = 0s )
7 0sno
 |-  0s e. No
8 7 a1i
 |-  ( ph -> 0s e. No )
9 8 8 1 pw2divsmuld
 |-  ( ph -> ( ( 0s /su ( 2s ^su N ) ) = 0s <-> ( ( 2s ^su N ) x.s 0s ) = 0s ) )
10 6 9 mpbird
 |-  ( ph -> ( 0s /su ( 2s ^su N ) ) = 0s )