Metamath Proof Explorer


Theorem pw2divs0d

Description: Division into zero is zero for a power of two. (Contributed by Scott Fenton, 21-Feb-2026)

Ref Expression
Hypothesis pw2divs0d.1 ⊢ ( 𝜑 → 𝑁 ∈ ℕ0s )
Assertion pw2divs0d ( 𝜑 → ( 0s /su ( 2s ↑s 𝑁 ) ) = 0s )

Proof

Step Hyp Ref Expression
1 pw2divs0d.1 ⊢ ( 𝜑 → 𝑁 ∈ ℕ0s )
2 2no ⊢ 2s ∈ No
3 expscl ⊢ ( ( 2s ∈ No ∧ 𝑁 ∈ ℕ0s ) → ( 2s ↑s 𝑁 ) ∈ No )
4 2 1 3 sylancr ⊢ ( 𝜑 → ( 2s ↑s 𝑁 ) ∈ No )
5 muls01 ⊢ ( ( 2s ↑s 𝑁 ) ∈ No → ( ( 2s ↑s 𝑁 ) ·s 0s ) = 0s )
6 4 5 syl ⊢ ( 𝜑 → ( ( 2s ↑s 𝑁 ) ·s 0s ) = 0s )
7 0no ⊢ 0s ∈ No
8 7 a1i ⊢ ( 𝜑 → 0s ∈ No )
9 8 8 1 pw2divmulsd ⊢ ( 𝜑 → ( ( 0s /su ( 2s ↑s 𝑁 ) ) = 0s ↔ ( ( 2s ↑s 𝑁 ) ·s 0s ) = 0s ) )
10 6 9 mpbird ⊢ ( 𝜑 → ( 0s /su ( 2s ↑s 𝑁 ) ) = 0s )