Metamath Proof Explorer


Theorem sbcieg

Description: Conversion of implicit substitution to explicit class substitution. (Contributed by NM, 10-Nov-2005)

Ref Expression
Hypothesis sbcieg.1
|- ( x = A -> ( ph <-> ps ) )
Assertion sbcieg
|- ( A e. V -> ( [. A / x ]. ph <-> ps ) )

Proof

Step Hyp Ref Expression
1 sbcieg.1
 |-  ( x = A -> ( ph <-> ps ) )
2 nfv
 |-  F/ x ps
3 2 1 sbciegf
 |-  ( A e. V -> ( [. A / x ]. ph <-> ps ) )