Metamath Proof Explorer


Theorem sbelx

Description: Elimination of substitution. Also see sbel2x . (Contributed by NM, 5-Aug-1993) Avoid ax-13 . (Revised by Wolf Lammen, 6-Aug-2023) Avoid ax-10 . (Revised by Gino Giotto, 20-Aug-2023)

Ref Expression
Assertion sbelx
|- ( ph <-> E. x ( x = y /\ [ x / y ] ph ) )

Proof

Step Hyp Ref Expression
1 sbequ12r
 |-  ( x = y -> ( [ x / y ] ph <-> ph ) )
2 1 equsexvw
 |-  ( E. x ( x = y /\ [ x / y ] ph ) <-> ph )
3 2 bicomi
 |-  ( ph <-> E. x ( x = y /\ [ x / y ] ph ) )