Metamath Proof Explorer


Theorem sbievOLD

Description: Obsolete proof of sbiev as of 18-Jul-2023. (Contributed by Wolf Lammen, 18-Jan-2023) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Hypotheses sbiev.1
|- F/ x ps
sbiev.2
|- ( x = y -> ( ph <-> ps ) )
Assertion sbievOLD
|- ( [ y / x ] ph <-> ps )

Proof

Step Hyp Ref Expression
1 sbiev.1
 |-  F/ x ps
2 sbiev.2
 |-  ( x = y -> ( ph <-> ps ) )
3 equsb1v
 |-  [ y / x ] x = y
4 2 sbimi
 |-  ( [ y / x ] x = y -> [ y / x ] ( ph <-> ps ) )
5 3 4 ax-mp
 |-  [ y / x ] ( ph <-> ps )
6 1 sbf
 |-  ( [ y / x ] ps <-> ps )
7 6 sblbisvOLD
 |-  ( [ y / x ] ( ph <-> ps ) <-> ( [ y / x ] ph <-> ps ) )
8 5 7 mpbi
 |-  ( [ y / x ] ph <-> ps )