Metamath Proof Explorer
Description: Inequality of an ordinal set with its successor. Does not use the axiom
of regularity. (Contributed by ML, 18-Oct-2020)
|
|
Ref |
Expression |
|
Hypotheses |
sucneqoni.1 |
|- X = suc Y |
|
|
sucneqoni.2 |
|- Y e. On |
|
Assertion |
sucneqoni |
|- X =/= Y |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
sucneqoni.1 |
|- X = suc Y |
2 |
|
sucneqoni.2 |
|- Y e. On |
3 |
1
|
a1i |
|- ( T. -> X = suc Y ) |
4 |
2
|
a1i |
|- ( T. -> Y e. On ) |
5 |
3 4
|
sucneqond |
|- ( T. -> X =/= Y ) |
6 |
5
|
mptru |
|- X =/= Y |