Metamath Proof Explorer


Theorem 3exp7

Description: 3 to the power of 7 equals 2187. (Contributed by metakunt, 21-Aug-2024)

Ref Expression
Assertion 3exp7 3 7 = 2187

Proof

Step Hyp Ref Expression
1 3nn0 3 0
2 6nn0 6 0
3 6p1e7 6 + 1 = 7
4 7nn0 7 0
5 2nn0 2 0
6 4 5 deccl 72 0
7 9nn0 9 0
8 2t3e6 2 3 = 6
9 3exp3 3 3 = 27
10 5 4 deccl 27 0
11 eqid 27 = 27
12 1nn0 1 0
13 8nn0 8 0
14 12 13 deccl 18 0
15 0nn0 0 0
16 5 dec0h 2 = 02
17 eqid 18 = 18
18 10 nn0cni 27
19 18 mul02i 0 27 = 0
20 6cn 6
21 ax-1cn 1
22 20 21 3 addcomli 1 + 6 = 7
23 19 22 oveq12i 0 27 + 1 + 6 = 0 + 7
24 7cn 7
25 24 addlidi 0 + 7 = 7
26 23 25 eqtri 0 27 + 1 + 6 = 7
27 13 dec0h 8 = 08
28 2t2e4 2 2 = 4
29 2cn 2
30 29 addlidi 0 + 2 = 2
31 28 30 oveq12i 2 2 + 0 + 2 = 4 + 2
32 4p2e6 4 + 2 = 6
33 31 32 eqtri 2 2 + 0 + 2 = 6
34 4nn0 4 0
35 7t2e14 7 2 = 14
36 24 29 35 mulcomli 2 7 = 14
37 1p1e2 1 + 1 = 2
38 8cn 8
39 4cn 4
40 8p4e12 8 + 4 = 12
41 38 39 40 addcomli 4 + 8 = 12
42 12 34 13 36 37 5 41 decaddci 2 7 + 8 = 22
43 5 4 15 13 11 27 5 5 5 33 42 decma2c 2 27 + 8 = 62
44 15 5 12 13 16 17 10 5 2 26 43 decmac 2 27 + 18 = 72
45 4p4e8 4 + 4 = 8
46 12 34 34 35 45 decaddi 7 2 + 4 = 18
47 7t7e49 7 7 = 49
48 4 5 4 11 7 34 46 47 decmul2c 7 27 = 189
49 10 5 4 11 7 14 44 48 decmul1c 27 27 = 729
50 1 1 8 9 49 numexp2x 3 6 = 729
51 eqid 72 = 72
52 7t3e21 7 3 = 21
53 1p0e1 1 + 0 = 1
54 5 12 15 52 53 decaddi 7 3 + 0 = 21
55 8 oveq1i 2 3 + 2 = 6 + 2
56 6p2e8 6 + 2 = 8
57 55 56 eqtri 2 3 + 2 = 8
58 4 5 15 5 51 16 1 54 57 decma 72 3 + 2 = 218
59 9t3e27 9 3 = 27
60 1 6 7 50 4 5 58 59 decmul1c 3 6 3 = 2187
61 1 2 3 60 numexpp1 3 7 = 2187