Metamath Proof Explorer


Theorem 3exp7

Description: 3 to the power of 7 equals 2187. (Contributed by metakunt, 21-Aug-2024)

Ref Expression
Assertion 3exp7 ⊢ 3 7 = 2187

Proof

Step Hyp Ref Expression
1 3nn0 ⊢ 3 ∈ ℕ 0
2 6nn0 ⊢ 6 ∈ ℕ 0
3 6p1e7 ⊢ 6 + 1 = 7
4 7nn0 ⊢ 7 ∈ ℕ 0
5 2nn0 ⊢ 2 ∈ ℕ 0
6 4 5 deccl ⊢ 72 ∈ ℕ 0
7 9nn0 ⊢ 9 ∈ ℕ 0
8 2t3e6 ⊢ 2 ⋅ 3 = 6
9 3exp3 ⊢ 3 3 = 27
10 5 4 deccl ⊢ 27 ∈ ℕ 0
11 eqid ⊢ 27 = 27
12 1nn0 ⊢ 1 ∈ ℕ 0
13 8nn0 ⊢ 8 ∈ ℕ 0
14 12 13 deccl ⊢ 18 ∈ ℕ 0
15 0nn0 ⊢ 0 ∈ ℕ 0
16 5 dec0h ⊢ 2 = 02
17 eqid ⊢ 18 = 18
18 10 nn0cni ⊢ 27 ∈ ℂ
19 18 mul02i ⊢ 0 ⋅ 27 = 0
20 6cn ⊢ 6 ∈ ℂ
21 ax-1cn ⊢ 1 ∈ ℂ
22 20 21 3 addcomli ⊢ 1 + 6 = 7
23 19 22 oveq12i ⊢ 0 ⋅ 27 + 1 + 6 = 0 + 7
24 7cn ⊢ 7 ∈ ℂ
25 24 addlidi ⊢ 0 + 7 = 7
26 23 25 eqtri ⊢ 0 ⋅ 27 + 1 + 6 = 7
27 13 dec0h ⊢ 8 = 08
28 2t2e4 ⊢ 2 ⋅ 2 = 4
29 2cn ⊢ 2 ∈ ℂ
30 29 addlidi ⊢ 0 + 2 = 2
31 28 30 oveq12i ⊢ 2 ⋅ 2 + 0 + 2 = 4 + 2
32 4p2e6 ⊢ 4 + 2 = 6
33 31 32 eqtri ⊢ 2 ⋅ 2 + 0 + 2 = 6
34 4nn0 ⊢ 4 ∈ ℕ 0
35 7t2e14 ⊢ 7 ⋅ 2 = 14
36 24 29 35 mulcomli ⊢ 2 ⋅ 7 = 14
37 1p1e2 ⊢ 1 + 1 = 2
38 8cn ⊢ 8 ∈ ℂ
39 4cn ⊢ 4 ∈ ℂ
40 8p4e12 ⊢ 8 + 4 = 12
41 38 39 40 addcomli ⊢ 4 + 8 = 12
42 12 34 13 36 37 5 41 decaddci ⊢ 2 ⋅ 7 + 8 = 22
43 5 4 15 13 11 27 5 5 5 33 42 decma2c ⊢ 2 ⋅ 27 + 8 = 62
44 15 5 12 13 16 17 10 5 2 26 43 decmac ⊢ 2 ⋅ 27 + 18 = 72
45 4p4e8 ⊢ 4 + 4 = 8
46 12 34 34 35 45 decaddi ⊢ 7 ⋅ 2 + 4 = 18
47 7t7e49 ⊢ 7 ⋅ 7 = 49
48 4 5 4 11 7 34 46 47 decmul2c ⊢ 7 ⋅ 27 = 189
49 10 5 4 11 7 14 44 48 decmul1c ⊢ 27 ⋅ 27 = 729
50 1 1 8 9 49 numexp2x ⊢ 3 6 = 729
51 eqid ⊢ 72 = 72
52 7t3e21 ⊢ 7 ⋅ 3 = 21
53 1p0e1 ⊢ 1 + 0 = 1
54 5 12 15 52 53 decaddi ⊢ 7 ⋅ 3 + 0 = 21
55 8 oveq1i ⊢ 2 ⋅ 3 + 2 = 6 + 2
56 6p2e8 ⊢ 6 + 2 = 8
57 55 56 eqtri ⊢ 2 ⋅ 3 + 2 = 8
58 4 5 15 5 51 16 1 54 57 decma ⊢ 72 ⋅ 3 + 2 = 218
59 9t3e27 ⊢ 9 ⋅ 3 = 27
60 1 6 7 50 4 5 58 59 decmul1c ⊢ 3 6 ⋅ 3 = 2187
61 1 2 3 60 numexpp1 ⊢ 3 7 = 2187