Metamath Proof Explorer


Theorem 3oai

Description: 3OA (weak) orthoarguesian law. Equation IV of GodowskiGreechie p. 249. (Contributed by NM, 19-Oct-1999) (New usage is discouraged.)

Ref Expression
Hypotheses 3oa.1 ⊢ A ∈ C ℋ
3oa.2 ⊢ B ∈ C ℋ
3oa.3 ⊢ C ∈ C ℋ
3oa.4 ⊢ R = ⊥ ⁡ B ∩ B ∨ ℋ A
3oa.5 ⊢ S = ⊥ ⁡ C ∩ C ∨ ℋ A
Assertion 3oai ⊢ B ∨ ℋ R ∩ C ∨ ℋ S ⊆ B ∨ ℋ R ∩ S ∨ ℋ B ∨ ℋ C ∩ R ∨ ℋ S

Proof

Step Hyp Ref Expression
1 3oa.1 ⊢ A ∈ C ℋ
2 3oa.2 ⊢ B ∈ C ℋ
3 3oa.3 ⊢ C ∈ C ℋ
4 3oa.4 ⊢ R = ⊥ ⁡ B ∩ B ∨ ℋ A
5 3oa.5 ⊢ S = ⊥ ⁡ C ∩ C ∨ ℋ A
6 1 2 3 4 5 3oalem5 ⊢ B + ℋ R ∩ C + ℋ S = B ∨ ℋ R ∩ C ∨ ℋ S
7 2 choccli ⊢ ⊥ ⁡ B ∈ C ℋ
8 2 1 chjcli ⊢ B ∨ ℋ A ∈ C ℋ
9 7 8 chincli ⊢ ⊥ ⁡ B ∩ B ∨ ℋ A ∈ C ℋ
10 4 9 eqeltri ⊢ R ∈ C ℋ
11 3 choccli ⊢ ⊥ ⁡ C ∈ C ℋ
12 3 1 chjcli ⊢ C ∨ ℋ A ∈ C ℋ
13 11 12 chincli ⊢ ⊥ ⁡ C ∩ C ∨ ℋ A ∈ C ℋ
14 5 13 eqeltri ⊢ S ∈ C ℋ
15 2 3 10 14 3oalem3 ⊢ B + ℋ R ∩ C + ℋ S ⊆ B + ℋ R ∩ S + ℋ B + ℋ C ∩ R + ℋ S
16 1 2 3 4 5 3oalem6 ⊢ B + ℋ R ∩ S + ℋ B + ℋ C ∩ R + ℋ S ⊆ B ∨ ℋ R ∩ S ∨ ℋ B ∨ ℋ C ∩ R ∨ ℋ S
17 15 16 sstri ⊢ B + ℋ R ∩ C + ℋ S ⊆ B ∨ ℋ R ∩ S ∨ ℋ B ∨ ℋ C ∩ R ∨ ℋ S
18 6 17 eqsstrri ⊢ B ∨ ℋ R ∩ C ∨ ℋ S ⊆ B ∨ ℋ R ∩ S ∨ ℋ B ∨ ℋ C ∩ R ∨ ℋ S