Metamath Proof Explorer


Theorem absimle

Description: The absolute value of a complex number is greater than or equal to the absolute value of its imaginary part. (Contributed by NM, 17-Mar-2005) (Proof shortened by Mario Carneiro, 29-May-2016)

Ref Expression
Assertion absimle ⊢ A ∈ ℂ → ℑ ⁡ A ≤ A

Proof

Step Hyp Ref Expression
1 negicn ⊢ − i ∈ ℂ
2 1 a1i ⊢ A ∈ ℂ → − i ∈ ℂ
3 id ⊢ A ∈ ℂ → A ∈ ℂ
4 2 3 mulcld ⊢ A ∈ ℂ → − i ⁢ A ∈ ℂ
5 absrele ⊢ − i ⁢ A ∈ ℂ → ℜ ⁡ − i ⁢ A ≤ − i ⁢ A
6 4 5 syl ⊢ A ∈ ℂ → ℜ ⁡ − i ⁢ A ≤ − i ⁢ A
7 imre ⊢ A ∈ ℂ → ℑ ⁡ A = ℜ ⁡ − i ⁢ A
8 7 fveq2d ⊢ A ∈ ℂ → ℑ ⁡ A = ℜ ⁡ − i ⁢ A
9 absmul ⊢ − i ∈ ℂ ∧ A ∈ ℂ → − i ⁢ A = − i ⁢ A
10 1 9 mpan ⊢ A ∈ ℂ → − i ⁢ A = − i ⁢ A
11 ax-icn ⊢ i ∈ ℂ
12 absneg ⊢ i ∈ ℂ → − i = i
13 11 12 ax-mp ⊢ − i = i
14 absi ⊢ i = 1
15 13 14 eqtri ⊢ − i = 1
16 15 oveq1i ⊢ − i ⁢ A = 1 ⁢ A
17 abscl ⊢ A ∈ ℂ → A ∈ ℝ
18 17 recnd ⊢ A ∈ ℂ → A ∈ ℂ
19 18 mullidd ⊢ A ∈ ℂ → 1 ⁢ A = A
20 16 19 eqtrid ⊢ A ∈ ℂ → − i ⁢ A = A
21 10 20 eqtr2d ⊢ A ∈ ℂ → A = − i ⁢ A
22 6 8 21 3brtr4d ⊢ A ∈ ℂ → ℑ ⁡ A ≤ A