Metamath Proof Explorer


Theorem absnegs

Description: Surreal absolute value of the negative. (Contributed by Scott Fenton, 16-Apr-2025)

Ref Expression
Assertion absnegs ⊢ A ∈ No → abs s ⁡ + s ⁡ A = abs s ⁡ A

Proof

Step Hyp Ref Expression
1 negnegs ⊢ A ∈ No → + s ⁡ + s ⁡ A = A
2 1 adantr ⊢ A ∈ No ∧ 0 s ≤ s A → + s ⁡ + s ⁡ A = A
3 negscl ⊢ A ∈ No → + s ⁡ A ∈ No
4 0no ⊢ 0 s ∈ No
5 4 a1i ⊢ A ∈ No → 0 s ∈ No
6 id ⊢ A ∈ No → A ∈ No
7 5 6 lenegsd ⊢ A ∈ No → 0 s ≤ s A ↔ + s ⁡ A ≤ s + s ⁡ 0 s
8 neg0s ⊢ + s ⁡ 0 s = 0 s
9 8 breq2i ⊢ + s ⁡ A ≤ s + s ⁡ 0 s ↔ + s ⁡ A ≤ s 0 s
10 7 9 bitrdi ⊢ A ∈ No → 0 s ≤ s A ↔ + s ⁡ A ≤ s 0 s
11 10 biimpa ⊢ A ∈ No ∧ 0 s ≤ s A → + s ⁡ A ≤ s 0 s
12 abssnid ⊢ + s ⁡ A ∈ No ∧ + s ⁡ A ≤ s 0 s → abs s ⁡ + s ⁡ A = + s ⁡ + s ⁡ A
13 3 11 12 syl2an2r ⊢ A ∈ No ∧ 0 s ≤ s A → abs s ⁡ + s ⁡ A = + s ⁡ + s ⁡ A
14 abssid ⊢ A ∈ No ∧ 0 s ≤ s A → abs s ⁡ A = A
15 2 13 14 3eqtr4d ⊢ A ∈ No ∧ 0 s ≤ s A → abs s ⁡ + s ⁡ A = abs s ⁡ A
16 6 5 lenegsd ⊢ A ∈ No → A ≤ s 0 s ↔ + s ⁡ 0 s ≤ s + s ⁡ A
17 8 breq1i ⊢ + s ⁡ 0 s ≤ s + s ⁡ A ↔ 0 s ≤ s + s ⁡ A
18 16 17 bitrdi ⊢ A ∈ No → A ≤ s 0 s ↔ 0 s ≤ s + s ⁡ A
19 18 biimpa ⊢ A ∈ No ∧ A ≤ s 0 s → 0 s ≤ s + s ⁡ A
20 abssid ⊢ + s ⁡ A ∈ No ∧ 0 s ≤ s + s ⁡ A → abs s ⁡ + s ⁡ A = + s ⁡ A
21 3 19 20 syl2an2r ⊢ A ∈ No ∧ A ≤ s 0 s → abs s ⁡ + s ⁡ A = + s ⁡ A
22 abssnid ⊢ A ∈ No ∧ A ≤ s 0 s → abs s ⁡ A = + s ⁡ A
23 21 22 eqtr4d ⊢ A ∈ No ∧ A ≤ s 0 s → abs s ⁡ + s ⁡ A = abs s ⁡ A
24 lestric ⊢ 0 s ∈ No ∧ A ∈ No → 0 s ≤ s A ∨ A ≤ s 0 s
25 4 24 mpan ⊢ A ∈ No → 0 s ≤ s A ∨ A ≤ s 0 s
26 15 23 25 mpjaodan ⊢ A ∈ No → abs s ⁡ + s ⁡ A = abs s ⁡ A