Metamath Proof Explorer


Theorem abvrcl

Description: Reverse closure for the absolute value set. (Contributed by Mario Carneiro, 8-Sep-2014)

Ref Expression
Hypothesis abvf.a ⊢ A = AbsVal ⁡ R
Assertion abvrcl ⊢ F ∈ A → R ∈ Ring

Proof

Step Hyp Ref Expression
1 abvf.a ⊢ A = AbsVal ⁡ R
2 df-abv ⊢ AbsVal = r ∈ Ring ⟼ f ∈ 0 +∞ Base r | ∀ x ∈ Base r f ⁡ x = 0 ↔ x = 0 r ∧ ∀ y ∈ Base r f ⁡ x ⋅ r y = f ⁡ x ⁢ f ⁡ y ∧ f ⁡ x + r y ≤ f ⁡ x + f ⁡ y
3 2 mptrcl ⊢ F ∈ AbsVal ⁡ R → R ∈ Ring
4 3 1 eleq2s ⊢ F ∈ A → R ∈ Ring