Metamath Proof Explorer


Theorem ackval50

Description: The Ackermann function at (5,0). (Contributed by AV, 9-May-2024)

Ref Expression
Assertion ackval50 ⊢ Ack ⁡ 5 ⁡ 0 = 65533

Proof

Step Hyp Ref Expression
1 df-5 ⊢ 5 = 4 + 1
2 1 fveq2i ⊢ Ack ⁡ 5 = Ack ⁡ 4 + 1
3 2 fveq1i ⊢ Ack ⁡ 5 ⁡ 0 = Ack ⁡ 4 + 1 ⁡ 0
4 4nn0 ⊢ 4 ∈ ℕ 0
5 ackvalsuc0val ⊢ 4 ∈ ℕ 0 → Ack ⁡ 4 + 1 ⁡ 0 = Ack ⁡ 4 ⁡ 1
6 4 5 ax-mp ⊢ Ack ⁡ 4 + 1 ⁡ 0 = Ack ⁡ 4 ⁡ 1
7 ackval41 ⊢ Ack ⁡ 4 ⁡ 1 = 65533
8 3 6 7 3eqtri ⊢ Ack ⁡ 5 ⁡ 0 = 65533