Metamath Proof Explorer


Theorem adds4d

Description: Rearrangement of four terms in a surreal sum. (Contributed by Scott Fenton, 5-Feb-2025)

Ref Expression
Hypotheses adds4d.1 ⊢ φ → A ∈ No
adds4d.2 ⊢ φ → B ∈ No
adds4d.3 ⊢ φ → C ∈ No
adds4d.4 ⊢ φ → D ∈ No
Assertion adds4d ⊢ φ → A + s B + s C + s D = A + s C + s B + s D

Proof

Step Hyp Ref Expression
1 adds4d.1 ⊢ φ → A ∈ No
2 adds4d.2 ⊢ φ → B ∈ No
3 adds4d.3 ⊢ φ → C ∈ No
4 adds4d.4 ⊢ φ → D ∈ No
5 1 2 3 adds32d ⊢ φ → A + s B + s C = A + s C + s B
6 5 oveq1d ⊢ φ → A + s B + s C + s D = A + s C + s B + s D
7 1 2 addscld ⊢ φ → A + s B ∈ No
8 7 3 4 addsassd ⊢ φ → A + s B + s C + s D = A + s B + s C + s D
9 1 3 addscld ⊢ φ → A + s C ∈ No
10 9 2 4 addsassd ⊢ φ → A + s C + s B + s D = A + s C + s B + s D
11 6 8 10 3eqtr3d ⊢ φ → A + s B + s C + s D = A + s C + s B + s D