Metamath Proof Explorer


Theorem ancomd

Description: Commutation of conjuncts in consequent. (Contributed by Jeff Hankins, 14-Aug-2009)

Ref Expression
Hypothesis ancomd.1 ⊢ φ → ψ ∧ χ
Assertion ancomd ⊢ φ → χ ∧ ψ

Proof

Step Hyp Ref Expression
1 ancomd.1 ⊢ φ → ψ ∧ χ
2 ancom ⊢ ψ ∧ χ ↔ χ ∧ ψ
3 1 2 sylib ⊢ φ → χ ∧ ψ