Metamath Proof Explorer


Theorem asclval

Description: Value of a mapped algebra scalar. (Contributed by Mario Carneiro, 8-Mar-2015)

Ref Expression
Hypotheses asclfval.a ⊢ A = algSc ⁡ W
asclfval.f ⊢ F = Scalar ⁡ W
asclfval.k ⊢ K = Base F
asclfval.s ⊢ · ˙ = ⋅ W
asclfval.o ⊢ 1 ˙ = 1 W
Assertion asclval ⊢ X ∈ K → A ⁡ X = X · ˙ 1 ˙

Proof

Step Hyp Ref Expression
1 asclfval.a ⊢ A = algSc ⁡ W
2 asclfval.f ⊢ F = Scalar ⁡ W
3 asclfval.k ⊢ K = Base F
4 asclfval.s ⊢ · ˙ = ⋅ W
5 asclfval.o ⊢ 1 ˙ = 1 W
6 oveq1 ⊢ x = X → x · ˙ 1 ˙ = X · ˙ 1 ˙
7 1 2 3 4 5 asclfval ⊢ A = x ∈ K ⟼ x · ˙ 1 ˙
8 ovex ⊢ X · ˙ 1 ˙ ∈ V
9 6 7 8 fvmpt ⊢ X ∈ K → A ⁡ X = X · ˙ 1 ˙