Metamath Proof Explorer


Theorem asclfval

Description: Function value of the algebra scalar lifting function. (Contributed by Mario Carneiro, 8-Mar-2015)

Ref Expression
Hypotheses asclfval.a ⊢ A = algSc ⁡ W
asclfval.f ⊢ F = Scalar ⁡ W
asclfval.k ⊢ K = Base F
asclfval.s ⊢ · ˙ = ⋅ W
asclfval.o ⊢ 1 ˙ = 1 W
Assertion asclfval ⊢ A = x ∈ K ⟼ x · ˙ 1 ˙

Proof

Step Hyp Ref Expression
1 asclfval.a ⊢ A = algSc ⁡ W
2 asclfval.f ⊢ F = Scalar ⁡ W
3 asclfval.k ⊢ K = Base F
4 asclfval.s ⊢ · ˙ = ⋅ W
5 asclfval.o ⊢ 1 ˙ = 1 W
6 fveq2 ⊢ w = W → Scalar ⁡ w = Scalar ⁡ W
7 6 2 eqtr4di ⊢ w = W → Scalar ⁡ w = F
8 7 fveq2d ⊢ w = W → Base Scalar ⁡ w = Base F
9 8 3 eqtr4di ⊢ w = W → Base Scalar ⁡ w = K
10 fveq2 ⊢ w = W → ⋅ w = ⋅ W
11 10 4 eqtr4di ⊢ w = W → ⋅ w = · ˙
12 eqidd ⊢ w = W → x = x
13 fveq2 ⊢ w = W → 1 w = 1 W
14 13 5 eqtr4di ⊢ w = W → 1 w = 1 ˙
15 11 12 14 oveq123d ⊢ w = W → x ⋅ w 1 w = x · ˙ 1 ˙
16 9 15 mpteq12dv ⊢ w = W → x ∈ Base Scalar ⁡ w ⟼ x ⋅ w 1 w = x ∈ K ⟼ x · ˙ 1 ˙
17 df-ascl ⊢ algSc = w ∈ V ⟼ x ∈ Base Scalar ⁡ w ⟼ x ⋅ w 1 w
18 16 17 3 mptfvmpt ⊢ W ∈ V → algSc ⁡ W = x ∈ K ⟼ x · ˙ 1 ˙
19 fvprc ⊢ ¬ W ∈ V → algSc ⁡ W = ∅
20 mpt0 ⊢ x ∈ ∅ ⟼ x · ˙ 1 ˙ = ∅
21 19 20 eqtr4di ⊢ ¬ W ∈ V → algSc ⁡ W = x ∈ ∅ ⟼ x · ˙ 1 ˙
22 fvprc ⊢ ¬ W ∈ V → Scalar ⁡ W = ∅
23 2 22 eqtrid ⊢ ¬ W ∈ V → F = ∅
24 23 fveq2d ⊢ ¬ W ∈ V → Base F = Base ∅
25 base0 ⊢ ∅ = Base ∅
26 24 25 eqtr4di ⊢ ¬ W ∈ V → Base F = ∅
27 3 26 eqtrid ⊢ ¬ W ∈ V → K = ∅
28 27 mpteq1d ⊢ ¬ W ∈ V → x ∈ K ⟼ x · ˙ 1 ˙ = x ∈ ∅ ⟼ x · ˙ 1 ˙
29 21 28 eqtr4d ⊢ ¬ W ∈ V → algSc ⁡ W = x ∈ K ⟼ x · ˙ 1 ˙
30 18 29 pm2.61i ⊢ algSc ⁡ W = x ∈ K ⟼ x · ˙ 1 ˙
31 1 30 eqtri ⊢ A = x ∈ K ⟼ x · ˙ 1 ˙