Metamath Proof Explorer


Theorem asclval

Description: Value of a mapped algebra scalar. (Contributed by Mario Carneiro, 8-Mar-2015)

Ref Expression
Hypotheses asclfval.a ⊢ 𝐴 = ( algSc ‘ 𝑊 )
asclfval.f ⊢ 𝐹 = ( Scalar ‘ 𝑊 )
asclfval.k ⊢ 𝐾 = ( Base ‘ 𝐹 )
asclfval.s ⊢ · = ( ·𝑠 ‘ 𝑊 )
asclfval.o ⊢ 1 = ( 1r ‘ 𝑊 )
Assertion asclval ( 𝑋 ∈ 𝐾 → ( 𝐴 ‘ 𝑋 ) = ( 𝑋 · 1 ) )

Proof

Step Hyp Ref Expression
1 asclfval.a ⊢ 𝐴 = ( algSc ‘ 𝑊 )
2 asclfval.f ⊢ 𝐹 = ( Scalar ‘ 𝑊 )
3 asclfval.k ⊢ 𝐾 = ( Base ‘ 𝐹 )
4 asclfval.s ⊢ · = ( ·𝑠 ‘ 𝑊 )
5 asclfval.o ⊢ 1 = ( 1r ‘ 𝑊 )
6 oveq1 ⊢ ( 𝑥 = 𝑋 → ( 𝑥 · 1 ) = ( 𝑋 · 1 ) )
7 1 2 3 4 5 asclfval ⊢ 𝐴 = ( 𝑥 ∈ 𝐾 ↦ ( 𝑥 · 1 ) )
8 ovex ⊢ ( 𝑋 · 1 ) ∈ V
9 6 7 8 fvmpt ⊢ ( 𝑋 ∈ 𝐾 → ( 𝐴 ‘ 𝑋 ) = ( 𝑋 · 1 ) )