Metamath Proof Explorer


Theorem asclfn

Description: Unconditional functionality of the algebra scalar lifting function. (Contributed by Mario Carneiro, 9-Mar-2015)

Ref Expression
Hypotheses asclfn.a ⊢ A = algSc ⁡ W
asclfn.f ⊢ F = Scalar ⁡ W
asclfn.k ⊢ K = Base F
Assertion asclfn ⊢ A Fn K

Proof

Step Hyp Ref Expression
1 asclfn.a ⊢ A = algSc ⁡ W
2 asclfn.f ⊢ F = Scalar ⁡ W
3 asclfn.k ⊢ K = Base F
4 ovex ⊢ x ⋅ W 1 W ∈ V
5 eqid ⊢ ⋅ W = ⋅ W
6 eqid ⊢ 1 W = 1 W
7 1 2 3 5 6 asclfval ⊢ A = x ∈ K ⟼ x ⋅ W 1 W
8 4 7 fnmpti ⊢ A Fn K