Metamath Proof Explorer


Theorem ax13b

Description: An equivalence between two ways of expressing ax-13 . See the comment for ax-13 . (Contributed by NM, 2-May-2017) (Proof shortened by Wolf Lammen, 26-Feb-2018) (Revised by BJ, 15-Sep-2020)

Ref Expression
Assertion ax13b ⊢ ¬ x = y → y = z → φ ↔ ¬ x = y → ¬ x = z → y = z → φ

Proof

Step Hyp Ref Expression
1 ax-1 ⊢ y = z → φ → ¬ x = z → y = z → φ
2 equeuclr ⊢ y = z → x = z → x = y
3 2 con3rr3 ⊢ ¬ x = y → y = z → ¬ x = z
4 3 imim1d ⊢ ¬ x = y → ¬ x = z → y = z → φ → y = z → y = z → φ
5 pm2.43 ⊢ y = z → y = z → φ → y = z → φ
6 4 5 syl6 ⊢ ¬ x = y → ¬ x = z → y = z → φ → y = z → φ
7 1 6 impbid2 ⊢ ¬ x = y → y = z → φ ↔ ¬ x = z → y = z → φ
8 7 pm5.74i ⊢ ¬ x = y → y = z → φ ↔ ¬ x = y → ¬ x = z → y = z → φ