Metamath Proof Explorer


Theorem ax13lem2

Description: Lemma for nfeqf2 . This lemma is equivalent to ax13v with one distinct variable constraint removed. (Contributed by Wolf Lammen, 8-Sep-2018) Reduce axiom usage. (Revised by Wolf Lammen, 18-Oct-2020) (New usage is discouraged.)

Ref Expression
Assertion ax13lem2 ⊢ ¬ x = y → ∃ x z = y → z = y

Proof

Step Hyp Ref Expression
1 ax13lem1 ⊢ ¬ x = y → w = y → ∀ x w = y
2 equeucl ⊢ z = y → w = y → z = w
3 2 eximi ⊢ ∃ x z = y → ∃ x w = y → z = w
4 19.36v ⊢ ∃ x w = y → z = w ↔ ∀ x w = y → z = w
5 3 4 sylib ⊢ ∃ x z = y → ∀ x w = y → z = w
6 1 5 syl9 ⊢ ¬ x = y → ∃ x z = y → w = y → z = w
7 6 alrimdv ⊢ ¬ x = y → ∃ x z = y → ∀ w w = y → z = w
8 equequ2 ⊢ w = y → z = w ↔ z = y
9 8 equsalvw ⊢ ∀ w w = y → z = w ↔ z = y
10 7 9 imbitrdi ⊢ ¬ x = y → ∃ x z = y → z = y