Metamath Proof Explorer


Theorem bdayfo

Description: The birthday function maps the surreals onto the ordinals. Axiom B of Alling p. 184. (Proof shortened on 14-Apr-2012 by SF). (Contributed by Scott Fenton, 11-Jun-2011)

Ref Expression
Assertion bdayfo ⊢ bday : No ⟶ onto On

Proof

Step Hyp Ref Expression
1 dmexg ⊢ x ∈ No → dom ⁡ x ∈ V
2 1 rgen ⊢ ∀ x ∈ No dom ⁡ x ∈ V
3 df-bday ⊢ bday = x ∈ No ⟼ dom ⁡ x
4 3 mptfng ⊢ ∀ x ∈ No dom ⁡ x ∈ V ↔ bday Fn No
5 2 4 mpbi ⊢ bday Fn No
6 3 rnmpt ⊢ ran ⁡ bday = y | ∃ x ∈ No y = dom ⁡ x
7 noxp1o ⊢ y ∈ On → y × 1 𝑜 ∈ No
8 1oex ⊢ 1 𝑜 ∈ V
9 8 snnz ⊢ 1 𝑜 ≠ ∅
10 dmxp ⊢ 1 𝑜 ≠ ∅ → dom ⁡ y × 1 𝑜 = y
11 9 10 ax-mp ⊢ dom ⁡ y × 1 𝑜 = y
12 11 eqcomi ⊢ y = dom ⁡ y × 1 𝑜
13 dmeq ⊢ x = y × 1 𝑜 → dom ⁡ x = dom ⁡ y × 1 𝑜
14 13 rspceeqv ⊢ y × 1 𝑜 ∈ No ∧ y = dom ⁡ y × 1 𝑜 → ∃ x ∈ No y = dom ⁡ x
15 7 12 14 sylancl ⊢ y ∈ On → ∃ x ∈ No y = dom ⁡ x
16 nodmon ⊢ x ∈ No → dom ⁡ x ∈ On
17 eleq1a ⊢ dom ⁡ x ∈ On → y = dom ⁡ x → y ∈ On
18 16 17 syl ⊢ x ∈ No → y = dom ⁡ x → y ∈ On
19 18 rexlimiv ⊢ ∃ x ∈ No y = dom ⁡ x → y ∈ On
20 15 19 impbii ⊢ y ∈ On ↔ ∃ x ∈ No y = dom ⁡ x
21 20 eqabi ⊢ On = y | ∃ x ∈ No y = dom ⁡ x
22 6 21 eqtr4i ⊢ ran ⁡ bday = On
23 df-fo ⊢ bday : No ⟶ onto On ↔ bday Fn No ∧ ran ⁡ bday = On
24 5 22 23 mpbir2an ⊢ bday : No ⟶ onto On