Metamath Proof Explorer


Theorem bj-cbvex4vv

Description: Version of cbvex4v with a disjoint variable condition, which does not require ax-13 . (Contributed by BJ, 16-Jun-2019) (Proof modification is discouraged.)

Ref Expression
Hypotheses bj-cbvex4vv.1 ⊢ x = v ∧ y = u → φ ↔ ψ
bj-cbvex4vv.2 ⊢ z = f ∧ w = g → ψ ↔ χ
Assertion bj-cbvex4vv ⊢ ∃ x ∃ y ∃ z ∃ w φ ↔ ∃ v ∃ u ∃ f ∃ g χ

Proof

Step Hyp Ref Expression
1 bj-cbvex4vv.1 ⊢ x = v ∧ y = u → φ ↔ ψ
2 bj-cbvex4vv.2 ⊢ z = f ∧ w = g → ψ ↔ χ
3 1 2exbidv ⊢ x = v ∧ y = u → ∃ z ∃ w φ ↔ ∃ z ∃ w ψ
4 3 cbvex2vw ⊢ ∃ x ∃ y ∃ z ∃ w φ ↔ ∃ v ∃ u ∃ z ∃ w ψ
5 2 cbvex2vw ⊢ ∃ z ∃ w ψ ↔ ∃ f ∃ g χ
6 5 2exbii ⊢ ∃ v ∃ u ∃ z ∃ w ψ ↔ ∃ v ∃ u ∃ f ∃ g χ
7 4 6 bitri ⊢ ∃ x ∃ y ∃ z ∃ w φ ↔ ∃ v ∃ u ∃ f ∃ g χ