Metamath Proof Explorer


Theorem bj-ceqsalg

Description: Remove from ceqsalg dependency on ax-ext (and on df-cleq and df-v ). See also bj-ceqsalgv . (Contributed by BJ, 12-Oct-2019) (Proof modification is discouraged.)

Ref Expression
Hypotheses bj-ceqsalg.1 ⊢ Ⅎ x ψ
bj-ceqsalg.2 ⊢ x = A → φ ↔ ψ
Assertion bj-ceqsalg ⊢ A ∈ V → ∀ x x = A → φ ↔ ψ

Proof

Step Hyp Ref Expression
1 bj-ceqsalg.1 ⊢ Ⅎ x ψ
2 bj-ceqsalg.2 ⊢ x = A → φ ↔ ψ
3 elisset ⊢ A ∈ V → ∃ x x = A
4 1 2 bj-ceqsalg0 ⊢ ∃ x x = A → ∀ x x = A → φ ↔ ψ
5 3 4 syl ⊢ A ∈ V → ∀ x x = A → φ ↔ ψ