Metamath Proof Explorer


Theorem bj-elsnb

Description: Biconditional version of elsng . (Contributed by BJ, 18-Nov-2023)

Ref Expression
Assertion bj-elsnb ⊢ A ∈ B ↔ A ∈ V ∧ A = B

Proof

Step Hyp Ref Expression
1 elex ⊢ A ∈ B → A ∈ V
2 elsng ⊢ A ∈ V → A ∈ B ↔ A = B
3 1 2 biadanii ⊢ A ∈ B ↔ A ∈ V ∧ A = B