Metamath Proof Explorer


Theorem bj-hbaeb

Description: Biconditional version of hbae . (Contributed by BJ, 6-Oct-2018) (Proof modification is discouraged.)

Ref Expression
Assertion bj-hbaeb ⊢ ∀ x x = y ↔ ∀ z ∀ x x = y

Proof

Step Hyp Ref Expression
1 bj-hbaeb2 ⊢ ∀ x x = y ↔ ∀ x ∀ z x = y
2 alcom ⊢ ∀ x ∀ z x = y ↔ ∀ z ∀ x x = y
3 1 2 bitri ⊢ ∀ x x = y ↔ ∀ z ∀ x x = y