Metamath Proof Explorer


Theorem bj-hbaeb2

Description: Biconditional version of a form of hbae with commuted quantifiers, not requiring ax-11 . (Contributed by BJ, 12-Dec-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-hbaeb2 ⊢ ∀ x x = y ↔ ∀ x ∀ z x = y

Proof

Step Hyp Ref Expression
1 sp ⊢ ∀ x x = y → x = y
2 axc9 ⊢ ¬ ∀ z z = x → ¬ ∀ z z = y → x = y → ∀ z x = y
3 1 2 syl7 ⊢ ¬ ∀ z z = x → ¬ ∀ z z = y → ∀ x x = y → ∀ z x = y
4 axc11r ⊢ ∀ z z = x → ∀ x x = y → ∀ z x = y
5 axc11 ⊢ ∀ x x = y → ∀ x x = y → ∀ y x = y
6 5 pm2.43i ⊢ ∀ x x = y → ∀ y x = y
7 axc11r ⊢ ∀ z z = y → ∀ y x = y → ∀ z x = y
8 6 7 syl5 ⊢ ∀ z z = y → ∀ x x = y → ∀ z x = y
9 3 4 8 pm2.61ii ⊢ ∀ x x = y → ∀ z x = y
10 9 axc4i ⊢ ∀ x x = y → ∀ x ∀ z x = y
11 sp ⊢ ∀ z x = y → x = y
12 11 alimi ⊢ ∀ x ∀ z x = y → ∀ x x = y
13 10 12 impbii ⊢ ∀ x x = y ↔ ∀ x ∀ z x = y