Metamath Proof Explorer


Theorem bj-nfexd

Description: Variant of nfexd . (Contributed by BJ, 25-Dec-2023)

Ref Expression
Hypotheses bj-nfald.1 ⊢ φ → ∀ y φ
bj-nfald.2 ⊢ φ → Ⅎ x ψ
Assertion bj-nfexd ⊢ φ → Ⅎ x ∃ y ψ

Proof

Step Hyp Ref Expression
1 bj-nfald.1 ⊢ φ → ∀ y φ
2 bj-nfald.2 ⊢ φ → Ⅎ x ψ
3 df-ex ⊢ ∃ y ψ ↔ ¬ ∀ y ¬ ψ
4 2 nfnd ⊢ φ → Ⅎ x ¬ ψ
5 1 4 bj-nfald ⊢ φ → Ⅎ x ∀ y ¬ ψ
6 5 nfnd ⊢ φ → Ⅎ x ¬ ∀ y ¬ ψ
7 3 6 nfxfrd ⊢ φ → Ⅎ x ∃ y ψ