Metamath Proof Explorer


Theorem bj-reabeq

Description: Relative form of eqabb . (Contributed by BJ, 27-Dec-2023)

Ref Expression
Assertion bj-reabeq ⊢ V ∩ A = x ∈ V | φ ↔ ∀ x ∈ V x ∈ A ↔ φ

Proof

Step Hyp Ref Expression
1 dfrab3 ⊢ x ∈ V | φ = V ∩ x | φ
2 1 eqeq2i ⊢ V ∩ A = x ∈ V | φ ↔ V ∩ A = V ∩ x | φ
3 nfcv ⊢ Ⅎ _ x A
4 nfab1 ⊢ Ⅎ _ x x | φ
5 nfcv ⊢ Ⅎ _ x V
6 3 4 5 bj-rcleqf ⊢ V ∩ A = V ∩ x | φ ↔ ∀ x ∈ V x ∈ A ↔ x ∈ x | φ
7 abid ⊢ x ∈ x | φ ↔ φ
8 7 bibi2i ⊢ x ∈ A ↔ x ∈ x | φ ↔ x ∈ A ↔ φ
9 8 ralbii ⊢ ∀ x ∈ V x ∈ A ↔ x ∈ x | φ ↔ ∀ x ∈ V x ∈ A ↔ φ
10 2 6 9 3bitri ⊢ V ∩ A = x ∈ V | φ ↔ ∀ x ∈ V x ∈ A ↔ φ