Metamath Proof Explorer


Theorem bj-xpimasn

Description: The image of a singleton, general case. [Change and relabel xpimasn accordingly, maybe to xpima2sn.] (Contributed by BJ, 6-Apr-2019)

Ref Expression
Assertion bj-xpimasn ⊢ A × B X = if X ∈ A B ∅

Proof

Step Hyp Ref Expression
1 xpima ⊢ A × B X = if A ∩ X = ∅ ∅ B
2 disjsn ⊢ A ∩ X = ∅ ↔ ¬ X ∈ A
3 eqid ⊢ B = B
4 2 3 ifbieq2i ⊢ if A ∩ X = ∅ ∅ B = if ¬ X ∈ A ∅ B
5 ifnot ⊢ if ¬ X ∈ A ∅ B = if X ∈ A B ∅
6 1 4 5 3eqtri ⊢ A × B X = if X ∈ A B ∅