Metamath Proof Explorer


Theorem bj-xpimasn

Description: The image of a singleton, general case. [Change and relabel xpimasn accordingly, maybe to xpima2sn.] (Contributed by BJ, 6-Apr-2019)

Ref Expression
Assertion bj-xpimasn ( ( 𝐴 × 𝐵 ) “ { 𝑋 } ) = if ( 𝑋 ∈ 𝐴 , 𝐵 , ∅ )

Proof

Step Hyp Ref Expression
1 xpima ⊢ ( ( 𝐴 × 𝐵 ) “ { 𝑋 } ) = if ( ( 𝐴 ∩ { 𝑋 } ) = ∅ , ∅ , 𝐵 )
2 disjsn ⊢ ( ( 𝐴 ∩ { 𝑋 } ) = ∅ ↔ ¬ 𝑋 ∈ 𝐴 )
3 eqid ⊢ 𝐵 = 𝐵
4 2 3 ifbieq2i ⊢ if ( ( 𝐴 ∩ { 𝑋 } ) = ∅ , ∅ , 𝐵 ) = if ( ¬ 𝑋 ∈ 𝐴 , ∅ , 𝐵 )
5 ifnot ⊢ if ( ¬ 𝑋 ∈ 𝐴 , ∅ , 𝐵 ) = if ( 𝑋 ∈ 𝐴 , 𝐵 , ∅ )
6 1 4 5 3eqtri ⊢ ( ( 𝐴 × 𝐵 ) “ { 𝑋 } ) = if ( 𝑋 ∈ 𝐴 , 𝐵 , ∅ )