Metamath Proof Explorer


Theorem breq1dd

Description: Equality deduction for a binary relation. (Contributed by Thierry Arnoux, 10-Jan-2026)

Ref Expression
Hypotheses breq1dd.1 ⊢ φ → A = B
breq1dd.2 ⊢ φ → A R C
Assertion breq1dd ⊢ φ → B R C

Proof

Step Hyp Ref Expression
1 breq1dd.1 ⊢ φ → A = B
2 breq1dd.2 ⊢ φ → A R C
3 1 breq1d ⊢ φ → A R C ↔ B R C
4 2 3 mpbid ⊢ φ → B R C