Metamath Proof Explorer


Theorem brgic

Description: The relation "is isomorphic to" for groups. (Contributed by Stefan O'Rear, 25-Jan-2015)

Ref Expression
Assertion brgic ⊢ R ≃ 𝑔 S ↔ R GrpIso S ≠ ∅

Proof

Step Hyp Ref Expression
1 df-gic ⊢ ≃ 𝑔 = GrpIso -1 V ∖ 1 𝑜
2 gimfn ⊢ GrpIso Fn Grp × Grp
3 1 2 brwitnlem ⊢ R ≃ 𝑔 S ↔ R GrpIso S ≠ ∅