Metamath Proof Explorer


Theorem cdlemc

Description: Lemma C in Crawley p. 113. (Contributed by NM, 26-May-2012)

Ref Expression
Hypotheses cdlemc3.l ⊢ ≤ ˙ = ≤ K
cdlemc3.j ⊢ ∨ ˙ = join ⁡ K
cdlemc3.m ⊢ ∧ ˙ = meet ⁡ K
cdlemc3.a ⊢ A = Atoms ⁡ K
cdlemc3.h ⊢ H = LHyp ⁡ K
cdlemc3.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemc3.r ⊢ R = trL ⁡ K ⁡ W
Assertion cdlemc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P → F ⁡ Q = Q ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ P ∨ ˙ Q ∧ ˙ W

Proof

Step Hyp Ref Expression
1 cdlemc3.l ⊢ ≤ ˙ = ≤ K
2 cdlemc3.j ⊢ ∨ ˙ = join ⁡ K
3 cdlemc3.m ⊢ ∧ ˙ = meet ⁡ K
4 cdlemc3.a ⊢ A = Atoms ⁡ K
5 cdlemc3.h ⊢ H = LHyp ⁡ K
6 cdlemc3.t ⊢ T = LTrn ⁡ K ⁡ W
7 cdlemc3.r ⊢ R = trL ⁡ K ⁡ W
8 simpl1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P = P → K ∈ HL ∧ W ∈ H
9 simpl2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P = P → F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W
10 simpr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P = P → F ⁡ P = P
11 1 2 3 4 5 6 7 cdlemc6 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ F ⁡ P = P → F ⁡ Q = Q ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ P ∨ ˙ Q ∧ ˙ W
12 8 9 10 11 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P = P → F ⁡ Q = Q ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ P ∨ ˙ Q ∧ ˙ W
13 simpl1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P ≠ P → K ∈ HL ∧ W ∈ H
14 simpl2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P ≠ P → F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W
15 simpl3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P ≠ P → ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P
16 simpr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P ≠ P → F ⁡ P ≠ P
17 1 2 3 4 5 6 7 cdlemc5 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P ≠ P → F ⁡ Q = Q ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ P ∨ ˙ Q ∧ ˙ W
18 13 14 15 16 17 syl112anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P ∧ F ⁡ P ≠ P → F ⁡ Q = Q ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ P ∨ ˙ Q ∧ ˙ W
19 12 18 pm2.61dane ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ ¬ Q ≤ ˙ P ∨ ˙ F ⁡ P → F ⁡ Q = Q ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ P ∨ ˙ Q ∧ ˙ W