Metamath Proof Explorer


Theorem cdlemftr1

Description: Part of proof of Lemma G of Crawley p. 116, sixth line of third paragraph on p. 117: there is "a translation h, different from the identity, such that tr h =/= tr f." (Contributed by NM, 25-Jul-2013)

Ref Expression
Hypotheses cdlemftr.b ⊢ B = Base K
cdlemftr.h ⊢ H = LHyp ⁡ K
cdlemftr.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemftr.r ⊢ R = trL ⁡ K ⁡ W
Assertion cdlemftr1 ⊢ K ∈ HL ∧ W ∈ H → ∃ f ∈ T f ≠ I ↾ B ∧ R ⁡ f ≠ X

Proof

Step Hyp Ref Expression
1 cdlemftr.b ⊢ B = Base K
2 cdlemftr.h ⊢ H = LHyp ⁡ K
3 cdlemftr.t ⊢ T = LTrn ⁡ K ⁡ W
4 cdlemftr.r ⊢ R = trL ⁡ K ⁡ W
5 1 2 3 4 cdlemftr2 ⊢ K ∈ HL ∧ W ∈ H → ∃ f ∈ T f ≠ I ↾ B ∧ R ⁡ f ≠ X ∧ R ⁡ f ≠ X
6 3simpa ⊢ f ≠ I ↾ B ∧ R ⁡ f ≠ X ∧ R ⁡ f ≠ X → f ≠ I ↾ B ∧ R ⁡ f ≠ X
7 6 reximi ⊢ ∃ f ∈ T f ≠ I ↾ B ∧ R ⁡ f ≠ X ∧ R ⁡ f ≠ X → ∃ f ∈ T f ≠ I ↾ B ∧ R ⁡ f ≠ X
8 5 7 syl ⊢ K ∈ HL ∧ W ∈ H → ∃ f ∈ T f ≠ I ↾ B ∧ R ⁡ f ≠ X