Metamath Proof Explorer


Theorem cdlemg2cex

Description: Any translation is one of our F s. TODO: fix comment, move to its own block maybe? Would this help for cdlemf ? (Contributed by NM, 22-Apr-2013)

Ref Expression
Hypotheses cdlemg2.b ⊢ B = Base K
cdlemg2.l ⊢ ≤ ˙ = ≤ K
cdlemg2.j ⊢ ∨ ˙ = join ⁡ K
cdlemg2.m ⊢ ∧ ˙ = meet ⁡ K
cdlemg2.a ⊢ A = Atoms ⁡ K
cdlemg2.h ⊢ H = LHyp ⁡ K
cdlemg2.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemg2ex.u ⊢ U = p ∨ ˙ q ∧ ˙ W
cdlemg2ex.d ⊢ D = t ∨ ˙ U ∧ ˙ q ∨ ˙ p ∨ ˙ t ∧ ˙ W
cdlemg2ex.e ⊢ E = p ∨ ˙ q ∧ ˙ D ∨ ˙ s ∨ ˙ t ∧ ˙ W
cdlemg2ex.g ⊢ G = x ∈ B ⟼ if p ≠ q ∧ ¬ x ≤ ˙ W ι z ∈ B | ∀ s ∈ A ¬ s ≤ ˙ W ∧ s ∨ ˙ x ∧ ˙ W = x → z = if s ≤ ˙ p ∨ ˙ q ι y ∈ B | ∀ t ∈ A ¬ t ≤ ˙ W ∧ ¬ t ≤ ˙ p ∨ ˙ q → y = E ⦋ s / t⦌ D ∨ ˙ x ∧ ˙ W x
Assertion cdlemg2cex ⊢ K ∈ HL ∧ W ∈ H → F ∈ T ↔ ∃ p ∈ A ∃ q ∈ A ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = G

Proof

Step Hyp Ref Expression
1 cdlemg2.b ⊢ B = Base K
2 cdlemg2.l ⊢ ≤ ˙ = ≤ K
3 cdlemg2.j ⊢ ∨ ˙ = join ⁡ K
4 cdlemg2.m ⊢ ∧ ˙ = meet ⁡ K
5 cdlemg2.a ⊢ A = Atoms ⁡ K
6 cdlemg2.h ⊢ H = LHyp ⁡ K
7 cdlemg2.t ⊢ T = LTrn ⁡ K ⁡ W
8 cdlemg2ex.u ⊢ U = p ∨ ˙ q ∧ ˙ W
9 cdlemg2ex.d ⊢ D = t ∨ ˙ U ∧ ˙ q ∨ ˙ p ∨ ˙ t ∧ ˙ W
10 cdlemg2ex.e ⊢ E = p ∨ ˙ q ∧ ˙ D ∨ ˙ s ∨ ˙ t ∧ ˙ W
11 cdlemg2ex.g ⊢ G = x ∈ B ⟼ if p ≠ q ∧ ¬ x ≤ ˙ W ι z ∈ B | ∀ s ∈ A ¬ s ≤ ˙ W ∧ s ∨ ˙ x ∧ ˙ W = x → z = if s ≤ ˙ p ∨ ˙ q ι y ∈ B | ∀ t ∈ A ¬ t ≤ ˙ W ∧ ¬ t ≤ ˙ p ∨ ˙ q → y = E ⦋ s / t⦌ D ∨ ˙ x ∧ ˙ W x
12 2 5 6 7 cdlemg1cex ⊢ K ∈ HL ∧ W ∈ H → F ∈ T ↔ ∃ p ∈ A ∃ q ∈ A ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = ι f ∈ T | f ⁡ p = q
13 simplll ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A ∧ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W → K ∈ HL
14 simpllr ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A ∧ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W → W ∈ H
15 simplrl ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A ∧ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W → p ∈ A
16 simprl ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A ∧ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W → ¬ p ≤ ˙ W
17 simplrr ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A ∧ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W → q ∈ A
18 simprr ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A ∧ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W → ¬ q ≤ ˙ W
19 eqid ⊢ ι f ∈ T | f ⁡ p = q = ι f ∈ T | f ⁡ p = q
20 1 2 3 4 5 6 8 9 10 11 7 19 cdlemg1b2 ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ ¬ p ≤ ˙ W ∧ q ∈ A ∧ ¬ q ≤ ˙ W → ι f ∈ T | f ⁡ p = q = G
21 13 14 15 16 17 18 20 syl222anc ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A ∧ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W → ι f ∈ T | f ⁡ p = q = G
22 21 eqeq2d ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A ∧ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W → F = ι f ∈ T | f ⁡ p = q ↔ F = G
23 22 pm5.32da ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A → ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = ι f ∈ T | f ⁡ p = q ↔ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = G
24 df-3an ⊢ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = ι f ∈ T | f ⁡ p = q ↔ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = ι f ∈ T | f ⁡ p = q
25 df-3an ⊢ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = G ↔ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = G
26 23 24 25 3bitr4g ⊢ K ∈ HL ∧ W ∈ H ∧ p ∈ A ∧ q ∈ A → ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = ι f ∈ T | f ⁡ p = q ↔ ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = G
27 26 2rexbidva ⊢ K ∈ HL ∧ W ∈ H → ∃ p ∈ A ∃ q ∈ A ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = ι f ∈ T | f ⁡ p = q ↔ ∃ p ∈ A ∃ q ∈ A ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = G
28 12 27 bitrd ⊢ K ∈ HL ∧ W ∈ H → F ∈ T ↔ ∃ p ∈ A ∃ q ∈ A ¬ p ≤ ˙ W ∧ ¬ q ≤ ˙ W ∧ F = G