Metamath Proof Explorer


Theorem cgrcomlrand

Description: Deduction form of cgrcomlr . (Contributed by Scott Fenton, 14-Oct-2013)

Ref Expression
Hypotheses cgrcomlrand.1 ⊢ φ → N ∈ ℕ
cgrcomlrand.2 ⊢ φ → A ∈ 𝔼 ⁡ N
cgrcomlrand.3 ⊢ φ → B ∈ 𝔼 ⁡ N
cgrcomlrand.4 ⊢ φ → C ∈ 𝔼 ⁡ N
cgrcomlrand.5 ⊢ φ → D ∈ 𝔼 ⁡ N
cgrcomlrand.6 ⊢ φ ∧ ψ → A B Cgr C D
Assertion cgrcomlrand ⊢ φ ∧ ψ → B A Cgr D C

Proof

Step Hyp Ref Expression
1 cgrcomlrand.1 ⊢ φ → N ∈ ℕ
2 cgrcomlrand.2 ⊢ φ → A ∈ 𝔼 ⁡ N
3 cgrcomlrand.3 ⊢ φ → B ∈ 𝔼 ⁡ N
4 cgrcomlrand.4 ⊢ φ → C ∈ 𝔼 ⁡ N
5 cgrcomlrand.5 ⊢ φ → D ∈ 𝔼 ⁡ N
6 cgrcomlrand.6 ⊢ φ ∧ ψ → A B Cgr C D
7 1 2 3 4 5 6 cgrcomrand ⊢ φ ∧ ψ → A B Cgr D C
8 1 2 3 5 4 7 cgrcomland ⊢ φ ∧ ψ → B A Cgr D C